A new treatise on the elements of the differential and integral calculus . he transformation oi rectangular into polar co-ordinatos, 276 DIFFERENTIAL CALCULUS. we have x z=zr cos. d^ y ^^r
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A new treatise on the elements of the differential and integral calculus . pposition, we have 1 + ^dxj dx and, through (2), this reduces to dx dx dx • •
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A new treatise on the elements of the differential and integral calculus . 5 = r sec. a + C, and the definite portion of the arc an-swering to ro, o,
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SOLVED:In Problems 15-22 find dx using implicit differenti- ation and then find the slope of the line tangent to the graph of the equation at the given point. 15. y3 _ Sy =
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SOLVED:point) Let g(x) be an invertible, differentiable function with values given in the table below. X 2 | 5 8 g(x) 8 2 g +21-0.25-0_ Find a formula for the tangent line
